The reaction between aluminium carbide and water takes place according to the following equation:
Calculate the volume fo methane measured at STP released from 14.4 g of aluminum carbide by excess fo water.
According to balance equation
Molar mass of aluminium carbide is 144 g
Number of moles of Aluminium carbide =14.4g144g=0.1mol
1 mol of aluminium carbide produce 3 moles of methane at STP.
1 mole = 22.4 L at STP
Therefore 3 mole = 3 × 22.4 L = 67.2 L of methane at STP
Or 1 mole of Aluminium carbide produce 67.2 L of methane at STP
therefore 0.1 mol of Aluminium carbide will produce =
= 6.72 L of methane