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Question

The reaction between chloroform, CHCl3(g) and chlorine Cl2(g) to form CCl4(g) and HCl(g) is believed to occur by this series of steps:
Step 1: Cl2(g)Cl(g)+Cl(g)
Step 2: CHCl3(g)+Cl(g)CCl3(g)+HCl(g)
Step 3: CCl3(g)+Cl(g)CCl4(g)
If this reaction is first order in CHCl3 and half order in Cl2, which statement about the relative rates of steps 1, 2 and 3 is correct?

A
Step 1 is the slowest
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B
Steps 1 and 2 must both be slow
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C
Step 2 must be slower than step 1
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D
Step 3 must be the slowest
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Solution

The correct option is C Step 2 must be slower than step 1
Given rate=k[CHCl3][Cl2]1/2
This rate can be obtained if step 2 is slower than step 1 and that step 1 is an equilibrium reaction.

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