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Stopping Potential

The reaction ...

Question

The reaction between $H_{2}$ and $B r_{2}$ to form $H B r$ in presence of light is initiated by the photo decomposition of $B r_{2}$ into free $B r$ atoms (free radicals) by absorption of light. The wavelength of $B r_{2}$ is:
[Given : $E = 1240$ eV]

10 ˚ A

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4500 ˚ A

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7800 ˚ A

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8000 ˚ A

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Solution

The correct option is A $10 ˚ A$
Energy $E$ and wavelength $λ$ can be related mathematically by the relation:

$E = \frac{h c}{λ}$

Where $h =$ Planck's constant and c= speed of light.

Using $h = 4.1357 \times 10^{- 15} e V s$ and

$c = 3 \times 10^{8} m / s = 3 \times 10^{18} ˚ A / s$

Therefore, $λ = \frac{h c}{E} = \frac{4.1357 \times 10^{- 15} \times 3 \times 10^{18}}{1240}$

$λ = 10 ˚ A$

Option A is the correct answer.

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