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Standard XII

Chemistry

Enthalpy

The reaction ...

Question

The reaction between $H_{2} O_{2}$ and $K M n O_{4}$ is $2 K M n O_{4} + 3 H_{2} S O_{4} + 5 H_{2} O_{2} \to K_{2} S O_{4} + 2 M n S O_{4} + 8 H_{2} O + 5 O_{2}$ .
In a reaction excess of $H_{2} O_{2}$ is added to 0.1 mole of acidified $K M n O_{4}$ solution. Then the STP volume of $O_{2}$ liberated is:

5.6 L

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6.6 L

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11.2 L

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22.4 L

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Solution

The correct option is A 5.6 L
$0.1$ mole of $K M n O_{4}$ produces $0.25$ moles of $O_{2}$ which has a volume of 22.4 x 0.25 litres at STP.

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Similar questions

Q. In a reaction excess of

H_{2} O_{2}

is added to

0.1

mole of acidfied

K M n O_{4}

solution. Then the STP volume of

O_{2}

liberated is?

Q. Given below are the two reactions of

H_{2} O_{2}

. Mark the correct statement which follows :
(i)

2 K M n O_{4} + 3 H_{2} S O_{4} + 5 H_{2} O_{2} \to K_{2} S O_{4} + 2 M n S O_{4} + 8 H_{2} O + 5 O_{2}

(ii)

2 C r (O H)_{3} + 4 N a O H + 3 H_{2} O_{2} \to 2 N a_{2} C r O_{4} + 8 H_{2} O

Q. A solution of

H_{2} O_{2}

is titrated against a solution of

K M n O_{4}

.
The reaction is,

2 {M n O_{4}}^{-} + 5 H_{2} O_{2} + 6 H^{+} \to 2 M n^{2 +} + 5 O_{2} + 8 H_{2} O

.
If it requires

46.9 m L

0.145 M K M n O_{4}

to oxidise

20 g

H_{2} O_{2}

, the mass percentage of

H_{2} O_{2}

in this solution is___________.

Q. In the reaction

2 K M n O_{4} + 3 H_{2} S O_{4} ⟶ K_{2} S O_{4} + 2 M n S O_{4} + 3 H_{2} O + 5 (O)

Equivalent weight of

K M n O_{4}

is (when molecular weight of

K M n O_{4} = 158

)

Q. A bottle of

H_{2} O_{2}

is labelled as

10

vol

H_{2} O_{2}

112

mL of this solution of

H_{2} O_{2}

is titrated against

0.04 M

acidified solution of

K M n O_{4}

. The volume of

K M n O_{4}

(in L) is :

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The reaction between H2O2 and KMnO4 is 2KMnO4+3H2SO4+5H2O2→K2SO4+2MnSO4+8H2O+5O2. In a reaction excess of H2O2 is added to 0.1 mole of acidified KMnO4 solution. Then the STP volume of O2 liberated is:

The correct option is A 5.6 L0.1 mole of KMnO4 produces 0.25 moles of O2 which has a volume of 22.4 x 0.25 litres at STP.

The correct option is A 5.6 L
$0.1$ mole of $K M n O_{4}$ produces $0.25$ moles of $O_{2}$ which has a volume of 22.4 x 0.25 litres at STP.