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Thermal Cracking

The reaction,...

Question

The reaction, $C_{12} H_{26} ⟶ C_{6} H_{12} + C_{6} H_{14}$ represents

Substitution

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Synthesis

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Cracking

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Polymerisation

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Solution

The correct option is C Cracking
$C_{12} H_{26} ⟶ C_{6} H_{12} + C_{6} H_{12}$
This reaction show breaking of higher boiling, less volatile hydrocarbons to lower boiling, more volatile hydrocarbons. So, this is the example of cracking.

Suggest Corrections

Similar questions

C_{12} H_{26} \to C_{6} H_{12} + C_{6} H_{14}

C_{12} H_{22} O_{11} + H_{2} O H^{+} - - \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

C_{12} H_{22} O_{11} + H_{2} O \to C_{6} H_{12} O_{6} + C_{6} H_{12} O_{6}

2.12 \times 10^{- 4} L {m o l}^{- 1} {s e c}^{- 1}

27^{o} C

1.07 \times 10^{5} J {m o l}^{- 1}

37^{o} C

C_{12} H_{22} O_{11} + H_{2} O I n v e r t a s e - ----- \to C_{6} H_{12} O_{6} A + C_{6} H_{12} O_{6} B

C_{6} H_{12} O_{6} z y m a s e - --- \to 2 C_{2} H_{5} O H + 2 {C O}_{2}

A

B

C_{6} H_{14}

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