The reaction $(C H_{3})_{3} C - B r H_{2} O ⟶ (C H_{3})_{3} - C - O H$ is a/an :

elimination reaction.

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substitution reaction.

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free radical reaction.

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displacement reaction.

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Solution

The correct option is C substitution reaction.
Substitution of $- B r$ by $- O H$ . So it is substitution reaction

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Similar questions

The reaction $(C H_{3})_{3} C$ -Br+ water ------- $>$ t-Butyl alcohol is:

(C H_{3})_{3} C C H = C H_{2} X - - \to T H F Y N a B H_{4} - --- \to N a O H (C H_{3})_{3} - C | O H - C H - C H_{3}

(C H_{3})_{3} C - C | H O H - C \equiv C - H H^{\oplus} - ------- \to i s o m e r i s a t i o n P r o d u c t

(I)

(I I)

(C H_{3})_{3} C - O H + H C l Z n C l_{2} - --- \to (C H_{3})_{3} C - C l + H_{2} O

(C H_{3})_{3} C C H = C H_{2} X - - \to T H F Y N a B H_{4} - --- \to N a O H (C H_{3})_{3} - C | O H - C H - C H_{3}

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