The reaction $C H_{3} B r + O H^{-} ⟶ C H_{3} O H + B r^{-}$ obeys the mechanism:

S_{N} 1

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S_{N} 2

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E_{1}

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E_{2}

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Solution

The correct option is B $S_{N} 2$
$C H_{3} B r + O H^{-} ⟶ C H_{3} O H + B r^{-}$ obeys $S_{N} 2$ mechanism in which bond breaking and bond formation is concerted. Usually primary alkyl halides and methyl halides undergo substitution by $S_{N} 2$ mechanism.

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Similar questions

C H_{3} B r + O H^{-} C_{2} H_{5} O H - ---- \to C H_{3} O H + B r^{-}

C H_{3} B r + O H^{-} (C H_{3})_{2} S O - ----- \to C H_{3} O H + B r^{-}

C H_{3} B r + O H^{-} \to C H_{3} O H + B r^{-}

S_{N} 1, S_{N} 2

E_{1}, E_{2}

How to know whether a reaction is following Sn1,Sn2,Sn ar,E1,E2 or E1cb mechanism?

please mention a way which does have any exceptions.

Which of the following is the example of SN² reaction

[CPMT 1999]

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