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Electromeric Effect

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The reaction CH4(g)+Cl_2(g) → CH_3Cl(g) + HCl(g) has △ H=-25 kcal and bond dissociation energy of C-Cl, H-Cl, C-H and Cl-Cl is given as 84 kcal/mol, 103 kcal/mol, x kcal/mol and y kcal/mol respectively. Given x:y =9:5, then bond energy of Cl-Cl bond in kcal/mol is (1) 57.57 (2) 67.75 (3) 70 (4) 80

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Q. The reaction

C H_{4} (g) + C l_{2} \to C H_{3} C l (g) + H C l (g)

δ H = - 25 k c a l .

From the data given below, what is the bond enthalpy of

C l - C l

Bond	Bond Energy (kcal)
$C - C$	$84$
$C - C l$	$81$
$C - H$	$x$
$C l - C l$	$y$
$H - C l$	$103$

x : y = 9 : 5

.

Q. The following reaction has

Δ H

- 25 k c a l

C H_{4} (g) + C l_{2} (g) \to C H_{3} C l (g) + H C l (g)

Bond	Bond Energy kCal
$ε_{C - C l}$	84
$ε_{H - C l}$	109
$ε_{C - H}$	$x$
$ε_{C l - C l}$	$y$
$x : y = 9 : 5$

From the given data, what is the bond enthalpy of

C l - C l

Q. Calculate the electronegativity of chlorine from the given data: bond energy of

C l - F

(61 k c a l m o l^{- 1})

F - F

(38 k c a l m o l^{- 1})

C l - C l

(58 k c a l m o l^{- 1})

and electronegativity of fluorine is

4.0

.

Q. Calculate the electronegativity of chlorine from bond energy of

C l - F

(61 k c a l m o l^{- 1})

F - F (38 k c a l m o l^{- 1})

C l - C l

(58 k c a l m o l^{- 1})

and electronegativity of fluorine

4.0 e V

.

Q. The bond dissociation energy of gaseous

H_{2}, C l_{2}

and HCl are 104, 58 and 103

k c a l m o l^{- 1}

respectively. The enthalpy of formation for

H C l

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