The reaction condition leading to best yields of $C_{2} H_{5} C l$ is

C_{2} H_{6} (e x c e s s) + C l_{2} U V l i g h t - ---- \to

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C_{2} H_{6} + C l_{2} D a r k - ----- \to r o o m t e m p

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C_{2} H_{6} + C l_{2} (e x c e s s) U V l i g h t - ---- \to

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C_{2} H_{6} + C l_{2} U V l i g h t - ---- \to

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Solution

The correct option is A $C_{2} H_{6} (e x c e s s) + C l_{2} U V l i g h t - ---- \to$
Yield of photochlorination is maximum when it takes place in UV light and the reagent to be chlorinated is in excess.

So, the reaction condition leading to best yields of $C_{2} H_{5} C l$ is
$C_{2} H_{6} (e x c e s s) + C l_{2} U V l i g h t - ---- \to C_{2} H_{5} C l$

Hence, Option "A" is the correct answer.

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Similar questions

Condition for maximum yield of $C_{2} H_{5} C l$ is

C_{2} H_{5} C l

Condition for maximum yield of $C_{2} H_{5} C l$ is

C_{2} H_{5} C l

C_{2} H_{6} + C l_{2} \to H C l + C_{2} H_{5} C l

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