Question

The reaction condition leading to the best yield of $C_2{H}_{5}Cl$ are:

• A. $C_2{H}_6\left(excess\right)+C{l}_2\stackrel{hvorheat}{\to }$
• B. $C_2{H}_6\left(excess\right)+C{l}_2\stackrel{hvorheat}{\to }$
• C. $C_2{H}_6+C{l}_2\left(excess\right)\underset{Roomtemperature}{\overset{dark}{\to }}$
• D. $C_2{H}_6+C{l}_2\stackrel{hvorheat}{\to }$

Answer 1

The correct option is B $C_2{H}_6\left(excess\right)+C{l}_2\stackrel{hvorheat}{\to }$

During chlorination of alkane, if excess of alkane is treated with $C{l}_2\left(g\right)$ in presence of light or heat, chance of mono-chlroination predominate.
$C_2{H}_6\left(excess\right)+C{l}_2\stackrel{hvorheat}{\to }C{H}_{3}C{H}_{2}Cl+HCl$