Question

The reaction condition leading to the best yield of $C_2{H}_{5}Cl$ is:

• A. $C_2{H}_6\left(\text{excess}\right)+C{l}_2\stackrel{\text{UV light}}{\to }$
• B. $C_2{H}_6+C{l}_2\text{(excess)}\underset{\text{room temp.}}{\overset{\text{dark}}{\to }}$
• C. $C_2{H}_6+C{l}_2\text{(excess)}\stackrel{\text{UV light}}{\to }$
• D. $C_2{H}_6+C{l}_2\stackrel{HCl}{\to }$

Answer 1

The correct option is A $C_2{H}_6\left(\text{excess}\right)+C{l}_2\stackrel{\text{UV light}}{\to }$

During chlorination of alkane, if excess of alkane is treated with $C{l}_2\left(g\right)$ in presence of light or heat, chance of mono-chlorinated product predominates.
$C_2{H}_6\text{(excess)}+C{l}_2\stackrel{\text{UV-light}}{\to }C{H}_{3}C{H}_{2}Cl+HCl$

Excess of $C{l}_2$ can lead to formation of dichloro, trichloro etc, products.