Question

The reaction conditions leading to the best yield of $C_2{H}_{5}Cl$ are:

• A. $C_2{H}_6\left(excess\right)+C{l}_2\to$
• B. $C_2{H}_6+C{l}_2\to$
• C. $C_2{H}_6+C{l}_2\left(excess\right)\to$
• D. none of these

Answer 1

Answer: (A)

$C_2{H}_6\left(excess\right)+C{l}_2\to$

Halogenation of alkanes will lead to the formation of alkyl halide.

In this reaction, if we use $C{l}_2$ in excess, then dichloro and trichloro forms as product and if ethane is used in excess, ethyl chloride forms as major product.

So, the reaction takes place as follows:
$C_2{H}_6+C{l}_2\to C_2{H}_{5}Cl+HCl$

(excess)

Option A is correct.