The reaction equation of the preparation of $H C l$ by synthesis is given by:

N a C l + H_{2} S O_{4} \to N a H S O_{4} + H C l

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N a H S O_{4} + N a C l \to H C l + N a S O_{4}

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H_{2} + C l_{2} \to 2 H C l

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None of these

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Solution

The correct option is C $H_{2} + C l_{2} \to 2 H C l$
In the chloralkali process, brine (mixture of sodium chloride and water) solution is electrolyzed producing chlorine (Cl $_{2}$ ), sodium hydroxide, and hydrogen (H $_{2}$ ):

2 NaCl + 2 H $_{2}$ O → Cl $_{2}$ + 2 NaOH + H $_{2}$

The pure chlorine gas can be combined with hydrogen to produce hydrogen chloride in the presence of UV light:

Cl $_{2}$ (g) + H $_{2}$ (g) → 2 HCl(g)

As the reaction is exothermic, the installation is called an HCl oven or HCl burner. The resulting hydrogen chloride gas is absorbed in deionized water, resulting in chemically pure hydrochloric acid. This reaction can give a very pure product, e.g. for use in the food industry.

Hence, the correct option is $C$

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Similar questions

N a C l + H_{2} S O_{4} ⟶ N a H S O_{4} + H C l

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H_{2} S O_{4}

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H C l

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