The reaction, $H_{2} S + H_{2} O_{2} \to 2 H_{2} O + S$ , shows___________.

Acidic nature of

H_{2} O_{2}

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Reducing nature of

H_{2} O_{2}

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Oxidising action of

H_{2} O_{2}

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Alkaline nature of

H_{2} O_{2}

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Solution

The correct option is C Oxidising action of $H_{2} O_{2}$
In $H_{2} O_{2}$ ,oxidation number of oxygen is -1 and in $H_{2} O$ it has -2 oxidation number so $H_{2} O_{2}$ is reduced.So this reaction show oxidising action of $H_{2} O_{2}$ which oxidises sulphur from -2 to 0 oxidation state and itself being reduced.

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