The reaction involved in reduction of $N A D^{+}$ is

Glucose--> Glucose 6-P

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Fructose 1, 6- diphosphate>PGAL+DiBAP

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Glucose 6-P -->Fructose 6 -P

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PGAL --> PGA

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Solution

The correct option is B PGAL --> PGA
This reaction takes place during glycolysis that involves a breakdown of glucose the reduction of NAD takes place and it forms in NADH+ H⁺.
This occurs when 1,3- phosphoglyceraldehyde is converted into 13-phosphoglyceric acid. The enzyme used here is triose phosphate dehydrogenase.
So, the correct option is 'PGAL --> PGA.'

Suggest Corrections

List-I (Enzyme)	List-II( Conversions)
a. Phosphogluco isomerase	$1$ . Fructose $\to$ Glucose
b. Triose phosphate isomerase	$2$ . Glucose $\to$ Glucose- $6$ -Phosphate
c. Fructose diphosphate aldolase	$3$ . Glucose- $6$ -phosphate $\to$ Fructose- $6$ -phosphate
d. Hexokinase	$4$ . Glyceraldehydes- $3$ -phosphate $\to$ Dihydroxy acetone phosphate
	$5$ . Fructose- $1$ , $6$ -diphosphate $\to$ Glyceraldehydes- $3$ -phosphate

	I.		II.
$1$ .	Fructose $1, 6$ diphosphate $\to 3$ PGAL $+$ DHAP	a.	Enolase
$2$ .	Citrate $\to$ Cis - aconitate	b.	Thiokinase
$3$ .	Succinyl Co. A $\to$ Succinate	c.	Aconitase
$4$ .	$2$ PGA $\to$ PEPA	d.	Aldolase