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Standard X

Chemistry

Factors Affecting the Rate of a Chemical Reaction

The reaction ...

Question

The reaction is given below, the rate constant for disappearance of A is $7.48 \times 10^{- 3} s e c^{- 1}$ . The time required for the total pressure in a system containing A at an initial pressure of 0.1 atm to rise to 0.145 atm is:
$2 A (g) \to 4 B (g) + C (g)$

0.80 min

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Solution

The correct option is A 0.80 min
Its a first order reaction and for this,
$k t = 2.303 l o g (\frac{a}{a - x})$

Here,
$2 A (g) \to 4 B (g) + C (g)$
P - -
P-2x 4x x

So here, P-2x+4x+x= 0.145
From given condition 2x is 0.03 and $t = \frac{2.303}{k} l o g (\frac{p}{p - 2 x}) = 47.63 s e c o n d s = 0.80$ min.

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Similar questions

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The reaction is given below, the rate constant for disappearance of A is 7.48×10−3sec−1. The time required for the total pressure in a system containing A at an initial pressure of 0.1 atm to rise to 0.145 atm is:2A(g)→4B(g)+C(g)

The correct option is A 0.80 minIts a first order reaction and for this,kt=2.303 log(aa−x) Here,2A(g)→4B(g)+C(g) P - - P-2x 4x xSo here, P-2x+4x+x= 0.145From given condition 2x is 0.03 and t=2.303k log(pp−2x)=47.63 seconds=0.80 min.

The reaction is given below, the rate constant for disappearance of A is $7.48 \times 10^{- 3} s e c^{- 1}$ . The time required for the total pressure in a system containing A at an initial pressure of 0.1 atm to rise to 0.145 atm is:
$2 A (g) \to 4 B (g) + C (g)$