You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard X

Chemistry

Factors Affecting the Rate of a Chemical Reaction

The reaction ...

Question

The reaction is given below, the rate constant for disappearance of A is $7.48 \times 10^{- 3} s e c^{- 1}$ . The time required for the total pressure in a system containing A at an initial pressure of 0.1 atm to rise to 0.145 atm is:
$2 A (g) \to 4 B (g) + C (g)$

0.80 min

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

0.567 min

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.433 min

No worries! We‘ve got your back. Try BYJU‘S free classes today!

0.344 min

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A 0.80 min
Its a first order reaction and for this,
$k t = 2.303 l o g (\frac{a}{a - x})$

Here,
$2 A (g) \to 4 B (g) + C (g)$
P - -
P-2x 4x x

So here, P-2x+4x+x= 0.145
From given condition 2x is 0.03 and $t = \frac{2.303}{k} l o g (\frac{p}{p - 2 x}) = 47.63 s e c o n d s = 0.80$ min.

Suggest Corrections

Similar questions

Q. The reaction given below, is observed to be a first order with rate constant

7.5 \times 10^{- 3} s^{- 1}

. Calculate the time required for the total pressure in a system containing A at an initial pressure of

0.1 a t m

to rise to

0.145 a t m

$2 A (g) \to 4 B (g) + C (g)$

Q. For the reaction,

A (g) + 2 B (g) ⟶ C (g) + D (g)

\frac{d x}{d t} = k [A] {[B]}^{2}

Initial pressure of A and B are respectively

0.60

atm and

0.80

atm, At a time when the pressure of C is

0.20

atm, rate of the reaction, relative to the initial value is:

Q. The reaction

A (g) + 2 B (g) \to C (g) + D (g)

is an elementary process. In an experiment, the initial partial pressure of A and B are

P_{A} = 0.60

atm and

P_{B} = 0.80

atm. When

P_{C} = 0.2

atm the rate of reaction relative to the initial rate is:

Q. For the reaction

A (g) + 2 B (g) \to C (g) + D (g); \frac{d x}{d t} = k [A] [B]^{2} .

Initial pressure of

A

and

B

are respectively

0.60 a t m

and

0.80 a t m

. At a time when pressure of

C

0.20 a t m

rate of the reaction, relative to the initial value is :

Q. A closed vessel initially contains a mixture of two gases

A_{2} B

and an inert gas. During the thermal decomposition of gas

A_{2} B

as per given

A_{2} B (g) \to 2 A (g) + B (g)

the pressure changed from an initial value of

2 a t m

5.2 a t m

at the end of reaction. The rate constant (in min) if total pressure was measured as

4.8 a t m

after

10 m i n

is:

Join BYJU'S Learning Program

The reaction is given below, the rate constant for disappearance of A is 7.48×10−3sec−1. The time required for the total pressure in a system containing A at an initial pressure of 0.1 atm to rise to 0.145 atm is:2A(g)→4B(g)+C(g)

The correct option is A 0.80 minIts a first order reaction and for this,kt=2.303 log(aa−x) Here,2A(g)→4B(g)+C(g) P - - P-2x 4x xSo here, P-2x+4x+x= 0.145From given condition 2x is 0.03 and t=2.303k log(pp−2x)=47.63 seconds=0.80 min.

The reaction is given below, the rate constant for disappearance of A is $7.48 \times 10^{- 3} s e c^{- 1}$ . The time required for the total pressure in a system containing A at an initial pressure of 0.1 atm to rise to 0.145 atm is:
$2 A (g) \to 4 B (g) + C (g)$