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Characteristics of Equilibrium Constant

The reaction ...

Question

The reaction : $N_{2} + {3 H}_{2} ⇋ {2 N H}_{3}$ takes places at $450^{o} C$ . 1 mole of $N_{2}$ and $2$ mole of $H_{2}$ are mixed in a 1 litre vessel and 1 mole of ${N H}_{3}$ is formed at equilibrium. Then $K_{c}$ for the above reaction is:

A

4

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B

8

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C

16

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D

32

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Solution

The correct option is C $16$
$N_{2} + 3 H_{2} ⇌ 2 N H_{3}$ given that: $2 x = 1, x = 0.5$
$1$ $2$ 0
$1 - x$ $2 - 3 x$ $2 x$
$0.5$ $0.5$ $1$
$K c = \frac{1^{2}}{(0.5)^{3} \times (0.5)}$
$= \frac{1}{{(\frac{5}{10})}^{4}} = 16$

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