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Standard XII

Chemistry

Effective Equilibrium Constant

The reaction ...

Question

The reaction $N_{2} + 3 H_{2} ⇌ 2 N H_{3}$ is started with initial number of moles of 1,2 and 3 for $N_{2}, H_{2}, N H_{3}$ in a 1 L vessel. If $x$ moles of $N_{2}$ under go dissociation then at equilibrium the number of moles of each substance remaining are:

1 - x, 2 - 3 x, 2 x

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1 - x / 3, 2 - x, x / 3

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1 - x, 2 - x, 3 + x

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1 - x, 2 - 3 x, 3 + 2 x

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Solution

The correct option is D $1 - x, 2 - 3 x, 3 + 2 x$
Initial moles at Equilibrium:
$N_{2} + 3 H_{2} ⇌ 2 N H_{3}$

$1$ $2$ $3$
$1 - x$ $2 - 3 x$ $3 + 2 x$

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Similar questions

Q. The reaction

N_{2} + 3 H_{2} ⟺ 2 N H_{3}

takes place at

450^{0} C

. 1 mole of

N_{2}

and 2 mole of

H_{2}

are mixed in a 1 litre vessel and 1 mole of

N H_{3}

is formed at equilibrium. Then Kc for the above reaction is ?

Q. In the process

N_{2} + 3 H_{2} ⇋ 2 N H_{3}

, the initial concentration of nitrogen and hydrogen are

1

mole per litre and

3

moles per litre respectively. The equilibrium constant of the reaction is

x

. The value of

K_{c}

for

2 N H_{3} ⇋ N_{2} + 3 H_{2}

will be:

Q. In a three litre vessel, 2 moles of

N_{2}

and 3 moles of length

H_{2}

are taken. If at equilibrium x moles of

N_{2}

were obtained then the concentration of

N H_{3}

at equilibrium will be:

Q. Consider the following reaction equilibrium:

N_{2} (g) + 3 H_{2} (g) ⇌ 2 N H_{3} (g)

. Initially, 1 mole of

N_{2}

and 3 moles of

H_{2}

are taken in a 2 litre flask.

At equilibrium state, if the number of moles of

N_{2}

is 0.6, then the total number moles of all gases present in the flask are:

Q. A mixture of

N_{2}

and

H_{2}

in the volume ratio

1 : 3

is allowed to attain equilibrium :

N_{2} + 3 H_{2} ⇌ 2 N H_{3}

670 K

and 1000 atm, 0.2491 mole fraction of

N H_{3}

is formed.

K_{p}

X \times 10^{- 6} {a t m}^{- 2}

100 X

is__________.

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The reaction N2+3H2⇌2NH3 is started with initial number of moles of 1,2 and 3 for N2,H2,NH3 in a 1 L vessel. If x moles of N2 under go dissociation then at equilibrium the number of moles of each substance remaining are:

The correct option is D 1−x,2−3x,3+2xInitial moles at Equilibrium:N2 + 3H2⇌2NH3123 1−x 2−3x 3+2x

The reaction $N_{2} + 3 H_{2} ⇌ 2 N H_{3}$ is started with initial number of moles of 1,2 and 3 for $N_{2}, H_{2}, N H_{3}$ in a 1 L vessel. If $x$ moles of $N_{2}$ under go dissociation then at equilibrium the number of moles of each substance remaining are:

The correct option is D $1 - x, 2 - 3 x, 3 + 2 x$
Initial moles at Equilibrium:
$N_{2} + 3 H_{2} ⇌ 2 N H_{3}$

$1$ $2$ $3$
$1 - x$ $2 - 3 x$ $3 + 2 x$