The reaction, $N_{2} + 3 H_{2} ⇌ 2 N H_{3}$ would be favoured by

high pressure

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low pressure

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both high and low pressure

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zero pressure

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Solution

The correct option is A high pressure
Total number of moles of reactants is higher than the number of moles of product. When pressure is increased, the equilibrium will shift in the forward direction so that there is decrease in the total number of moles of the reaction mixture. This will nullify the effect of increased pressure.

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The reaction, N2+3H2⇌2NH3 would be favoured by

The reaction, $N_{2} + 3 H_{2} ⇌ 2 N H_{3}$ would be favoured by