The reaction of 1-butene with HBr in presence peroxides yields 1-bromobutane. The mechanism of reaction involves:
Chain propagation
CH3CH2CH=CH2+|¯¯¯¯¯¯¯Br–––⋅⟶CH3CH2˙CH−CH2Brsecondaryradical ΔHo∼−12.6kJ/mol
CH3CH2˙CH−CH2Brsecondaryradical+HBr⟶CH3CH2H|CH−CH2Br+|¯¯¯¯¯¯¯Br–––⋅ ΔHo∼−31.4kJ/mol
The reaction follows free radical mechanism and bromine radical is involved in the first step at propagation. Presence of peroxide first produce bromine radical.