The reaction of an amide with bromine and alkali to form a primary amine is called

Hunsdiecker reaction

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Hofmann mustard oil reaction

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Hoffmann degradation of amides

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Hell-Volhard-Zelinski reaction

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Solution

The correct option is B Hoffmann degradation of amides
The reaction of an amide with bromine and alkali to form a primary amine is called
Hoffmann degradation of amides.
$R C O N H_{2} + B r_{2} + 4 K O H \to R N H_{2} + 22 K B r + K_{2} C O_{3} + 2 H_{2} O$
The intermediates involved in the reaction are N bromoamide $R C O N H B r$ and isocyanate $R N C O$ .
For example propionamide on Hoffmann degradation gives ethyl amine.
$C H_{3} C H_{2} C O N H_{2} + B r_{2} + 4 K O H \to C H_{3} C H_{2} N H_{2} + 2 K B r + K_{2} C O_{3} + 2 H_{2} O$

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