Question

The reaction of aqueous $KMn{O}_4\text{with}{H}_2{O}_2$ in acidic condic conditions gives :

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• A. $M{n}^{2+}\text{and}{O}_2$
• B. $M{n}^{2+}\text{and}{O}_3$
• C. $M{n}^{4+}\text{and}Mn{O}_2$
• D. $M{n}^{4+}\text{and}{O}_2$

Answer 1

The correct option is A $M{n}^{2+}\text{and}{O}_2$

$3H_{2}S{O}_4+2KMn{O}_4+5H_2{O}_2\to 2MnS{O}_4+8H_{2}O+K_{2}S{O}_4$
Hence option (b) is correct