The reaction of aqueous $K M n O_{4}$ with $H_{2} O_{2}$ in acidic conditions gives:

M n^{4 +}

and

O_{2}

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M n^{2 +}

and

O_{2}

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M n^{2 +}

and

O_{3}

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M n^{4 +}

and

M n O_{2}

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Solution

The correct option is D $M n^{2 +}$ and $O_{2}$
The reaction of aqueous $K M n O_{4}$ with $H_{2} O_{2}$ in acidic conditions gives:

$3 H_{2} S O_{4} + 2 K M n O_{4} + 5 H_{2} O_{2} \to 5 O_{2} + 2 M n S O_{4} + 8 H_{2} O + K_{2} S O_{4}$

The oxidation number of $M n$ in $M n S O_{4}$ is $+ 2$ .

Hence, option $B$ is correct.

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