The reaction of benzaldehyde with $P h M g B r / H_{2} O$ followed by oxidation with $C r O_{2} C l_{2}$ will give:

benzophenone

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benzoic acid

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3-Phenylpropan-1-ol

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α

-hydroxyphenylacetic acid

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Solution

The correct option is A benzophenone
$P h M g B r / H_{2} O$ with benzaldehyde will give nucleophilic addition reaction, and $C r O_{2} C l_{2}$ will perform oxidation.
$P h M g B r + C_{6} H_{5} C H O H_{2} O ⟶ C_{6} H_{5} C H (O H) P h C r O_{2} C l_{2} ⟶ C_{6} H_{5} C = O (P h)$

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Similar questions

How will you bring about the following conversions in not more than two steps?

(i) Propanone to Propene

(ii) Benzoic acid to Benzaldehyde

(iii) Ethanol to 3-Hydroxybutanal

(iv) Benzene to m-Nitroacetophenone

(v) Benzaldehyde to Benzophenone

(vi) Bromobenzene to 1-Phenylethanol

(vii) Benzaldehyde to 3-Phenylpropan-1-ol

(viii) Benazaldehyde to α-Hydroxyphenylacetic acid

(ix) Benzoic acid to m- Nitrobenzyl alcohol

Look at this enamine:

Which of the following sequence converts benzaldehyde into the given enamine?

1: Oxidation with Cr(VI) compound
2: reaction with pyrrolidine with pH control; acid catalyst
3: $M e M g B r f o l l o w e d b y H_{3} O^{+}$

Q. Which of the following is/are formed on reaction of benzaldehyde with aqueous NaOH followed by acidification with dilute hydrochloric acid ?

Q. Aldehydes, Ketones and Carboxylic acids are Carbonyl compounds.
(a) Aldehydes differ from Ketones in their oxidation reactions. Illustrate with one example.
(b) How will you prepare benzaldehyde by Gatterman-Koch reaction?
(c) Write the reactions of carboxylic acid with the following reagents. (Write the chemical equations)
(i) Thionyl chloride

(S O {C l}_{2})

(ii) Chlorine in presence of small amount of red phosphorous.
(iii) Lithium Aluminium hydride

(L i A l H_{4})

/ether.

Q. Cinnamic acid from benzaldehyde would be prepared by which of the following reaction?

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The reaction of benzaldehyde with PhMgBr/H2O followed by oxidation with CrO2Cl2 will give:

The correct option is A benzophenonePhMgBr/H2O with benzaldehyde will give nucleophilic addition reaction, and CrO2Cl2 will perform oxidation.PhMgBr+C6H5CHOH2O⟶C6H5CH(OH)PhCrO2Cl2⟶C6H5C=O(Ph)

The reaction of benzaldehyde with $P h M g B r / H_{2} O$ followed by oxidation with $C r O_{2} C l_{2}$ will give:

The correct option is A benzophenone
$P h M g B r / H_{2} O$ with benzaldehyde will give nucleophilic addition reaction, and $C r O_{2} C l_{2}$ will perform oxidation.
$P h M g B r + C_{6} H_{5} C H O H_{2} O ⟶ C_{6} H_{5} C H (O H) P h C r O_{2} C l_{2} ⟶ C_{6} H_{5} C = O (P h)$