The reaction of $C_{6} H_{5} C H = {C H C H}_{3}$ with $H B r$ produces:

C_{6} H_{5} C H | B r {C H}_{2} {C H}_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

C_{6} H_{5} - {C H}_{2} C H | B r - {C H}_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C_{6} H_{5} {C H}_{2} {C H}_{2} {C H}_{2} B r

No worries! We‘ve got your back. Try BYJU‘S free classes today!

a mixture of these

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C_{6} H_{5} C H | B r {C H}_{2} {C H}_{3}$

Thus product A will be formed.

Suggest Corrections

Similar questions

C_{6} H_{5} - C H_{2} - C H = C H_{2} + H B r \to

C_{6} H_{5} - C H = C H_{2} + H B r P e r o x i d e - ---- \to

C_{6} H_{5} {C O N H C H}_{3}

C_{6} H_{5} {C H}_{2} {N H C H}_{3}

C_{6} H_{5} {N H}_{2}

C_{6} H_{5} {N H C H}_{3}

C_{6} H_{5} {C H}_{2} {N H}_{2}

C_{6} H_{5} {N H}_{2}

C_{6} H_{5} {N H C H}_{3}

C_{6} H_{5} {C H}_{2} {N H}_{2}

{C H}_{3} {N H}_{2}, {({C H}_{3})}_{2} N H, C_{6} H_{5} {N H}_{2}, C_{6} H_{5} {C H}_{2} {N H}_{2}

Join BYJU'S Learning Program