The reaction of $C H_{3} O C_{2} H_{5}$ with $H I$ gives:

C H_{3} I

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C_{2} H_{5} O H

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C H_{3} I + C_{2} H_{5} O H

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C_{2} H_{5} I + C H_{3} O H

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Solution

The correct option is B $C H_{3} I + C_{2} H_{5} O H$
When ethers are treated with a strong acid in the presence of a nucleophile, they can be cleaved to give alcohols and alkyl halides. If the ether is on a primary carbon this may occur through an $S N_{2}$ pathway. The reaction of $C H_{3} O C_{2} H_{5}$ with $H I$ gives $C H_{3} I + C_{2} H_{5} O H$ .

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