The reaction of ethylene glycol with ${P I}_{3}$ gives:

I {C H}_{2} - {C H}_{2} I

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{C H}_{2} = {C H}_{2}

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{C H}_{2} = C H I

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I C H = C H I

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Solution

The correct option is B ${C H}_{2} = {C H}_{2}$
The reaction of ethylene glycol with ${P I}_{3}$ gives ethylene ${C H}_{2} = {C H}_{2}$
$H O - {C H}_{2} - {C H}_{2} - O H {P I}_{3} - - \to I {C H}_{2} - {C H}_{2} I - I_{2} - - \to {C H}_{2} = {C H}_{2}$

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P

Q

C H_{3} - C H_{2} C \equiv C H (I)

C H_{3} - C \equiv C - C H_{3} (I I)

C H_{3} - C H_{2} - C H_{2} - C H_{3} (I I I)

C H_{3} - C H = C H_{2} (I V)

C H_{2} = C H_{2} + C H_{3} C O C l A l C l_{3} - -- \to

	Column I		Column II
A	$C H_{3} - C H B r - C D_{3}$ /on treatement with alc.KOH gives $C H_{2} = C H - C D_{3}$ as a major product	P	E1 reaction
B	$P h - C H B r - C H_{3}$ reacts faster than $P h - C H B r - C D_{3}$	Q	E2 reaction
C	$P h - C H_{2} - C H_{2} - F$ on treatement with $C_{2} H_{5} O D / C_{2} H_{5} O^{-}$ gives $P h - C D = C H_{2}$ as the major product	R	E1cB reaction
D	$P h - C H_{2} - C H_{2} - B r$ and $P h - C D_{2} - C H_{2} - B r$ react with same rate	S	First order reaction

C H_{3} - C H_{2} - C H_{3} | C H - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{2} - C H_{3} | C H - C H_{3}

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