wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The reaction of H3N3B3Cl3 (A) with LiBH4 in tetrahydrofuran gives inorganic benzene (B). Furthur, the reaction of (A) with (C) leads to H3N3B3(Me)3. Compounds (B) and (C) respectively, are:

A
Boron nitride, MeBr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
Diborane, MeMgBr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
Borazine, MeBr
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Borazine, MeMgBr
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D Borazine, MeMgBr
B3N3H3Cl3+LiBH4B3N3H6+LiCl+BCl3
B3N3H3Cl3+3CH3MgBrB3N3H3(CH3)3+3MgBrCl

So, we can say that,
B is B3N3H6
C is CH3MgBr

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Reactions of Haloalkanes
CHEMISTRY
Watch in App
Join BYJU'S Learning Program
CrossIcon