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Byju's Answer

Standard XII

Chemistry

Reaction with Metals

The reaction ...

Question

The reaction of $H_{3} N_{3} B_{3} C l_{3}$ (A) with $L i B H_{4}$ in tetrahydrofuran gives inorganic benzene (B). Furthur, the reaction of (A) with (C) leads to $H_{3} N_{3} B_{3} (M e)_{3}$ . Compounds (B) and (C) respectively, are:

Boron nitride,

M e B r

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Diborane,

M e M g B r

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Borazine,

M e B r

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Borazine,

M e M g B r

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Solution

The correct option is D Borazine, $M e M g B r$
$B_{3} N_{3} H_{3} C l_{3} + L i B H_{4} \to B_{3} N_{3} H_{6} + L i C l + B C l_{3}$
$B_{3} N_{3} H_{3} C l_{3} + 3 C H_{3} M g B r \to B_{3} N_{3} H_{3} (C H_{3})_{3} + 3 M g B r C l$

So, we can say that,
$B$ is $B_{3} N_{3} H_{6}$
$C$ is $C H_{3} M g B r$

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Similar questions

Q. The reaction of

H_{3} N_{3} B_{3} C l_{3} (A)

with

L i B H_{4}

in tetrahydrofurah gives inorganic benzene (B). Further, the reaction of (A) with (C) leads to

H_{3} N_{3} B_{3} (M e)_{3}

. Compounds (B) and (C) respectively, are:

Q. Borazine is sometimes called inorganic benzene. Which of the following reactions is expected to give this compound?

Q. Match the column I with column II and mark the appropriate choice.

	Column I		Column II
(A)	Borax - bead	(i)	Alum
(B)	Inorganic benzene	(ii)	Diborane
(C)	Antiseptic	(iii)	Metaborate
(D)	Bridged hydrogens	(iv)	Borazine

Q. Boron and nitrogen form bonds analogous to carbon-carbon bonds. For example, compound ammonia borane,

N H_{3} - B H_{3}

, contains

B - N

bond analogous to the

C - C

bond in ethane. Borazine

(B_{3} N_{3} H_{6})

is analogous to benzene and is prepared by reacting

N H_{4} C l

with

B C l_{4}

followed by reduction using

L i B H_{4}

. The correct statement(s) is/are:

Q. A compound of boron X reacts at

200^{\circ} C

temperature with

N H_{3}

to give another compound

Y

which is called as inorganic benzene. The compound

Y

is a colourless liquid and is highly sensitive. Its melting point is

- 57^{\circ} C

. The compound

X

with excess

N H_{3}

and at a still higher temperature gives boron nitride

{(B N)}_{n}

. The compounds

X

and

Y

respectively are:

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The reaction of H3N3B3Cl3 (A) with LiBH4 in tetrahydrofuran gives inorganic benzene (B). Furthur, the reaction of (A) with (C) leads to H3N3B3(Me)3. Compounds (B) and (C) respectively, are:

The correct option is D Borazine, MeMgBrB3N3H3Cl3+LiBH4→B3N3H6+LiCl+BCl3 B3N3H3Cl3+3CH3MgBr→B3N3H3(CH3)3+3MgBrCl So, we can say that, B is B3N3H6 C is CH3MgBr

The reaction of $H_{3} N_{3} B_{3} C l_{3}$ (A) with $L i B H_{4}$ in tetrahydrofuran gives inorganic benzene (B). Furthur, the reaction of (A) with (C) leads to $H_{3} N_{3} B_{3} (M e)_{3}$ . Compounds (B) and (C) respectively, are: