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Question

The reaction of heated graphite with superheated steam is endothermic;
C (graphite)+H2 O(g)CO g)+H2 (g) 1
The heat required for this reaction is provided by burning part of the graphite;
C (graphite)+O2 (g)CO2 (g);H(500K)=393.7 kJmol1 2.
If 1.34 mole of graphite is required for production of 1 mole of Hydrogen at 500 K.
What is H(500K) for reaction (1) ?

A
134 kJmol1
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B
144 kJmol1
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C
234 kJmol1
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D
244 kJmol1
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Solution

The correct option is A 134 kJmol1
C (g)+H2O (g)CO (g)+H2 (g)
heat required is provided by
C (g)+O2 (g)CO2 (g)
H(500K)=393.7 kJmol1
1.34 mole of graphite is required for production of 1 mole of hydrogen. To produce 1 mole hydrogen, 1 mole graphite will be required in first reaction.
This means that 0.34 mole extra substance is used for production of heat
H for reaction 0.34×393.7=133.85 kJmol1134 kJmol1

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