The reaction of slaked lime with Cl2 gas gives:
Slaked lime Ca(OH)2 with chlorine gives bleaching powder (CaOCl2). The reaction for which is given below:
2Ca(OH)2+2Cl2→Ca(OCl)2+CaCl2+2H2O.
So, option C is correct.
2Ca(OH)2 + 2Cl2 → A–– + B–– + 2H2O
A & B are
(CH3COO)2Pb+Ca(OH)2→A+(CH3COO)2Ca
A+CaOCl2→B+CaCl2+H2O Identify A and B.