Question

The reaction of Sodium methoxide with $R_{2}CHX$ is:

• A. ${SN}^1$
• B. ${SN}^2$
• C. Elimination
• D. Substitution

Answer 1

Answer: (A)

${SN}^1$

Sodium methoxide $\Rightarrow {CH}_3\stackrel{(-)}{O}\stackrel{+}{Na}$

As the corboncation formed is stable by inductive effect and hyper conjugation. It undergoes ${SN}^1$ reaction.

${SN}^1$ reaction means the formed carboncation should be stable.