The reaction of sodium thiosulphate with $I_{2}$ produces:

Sodium sulphite

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Sodium sulphate

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Sodium iodide

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Sodium tetrathionate

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Solution

The correct option is D
Sodium tetrathionate

$2 N a_{2} S_{2} O_{3} + I_{2} ⟶ N a_{2} S_{4} O_{6} + 2 N a I$

The products are Sodium tetrathionate and sodium iodide.

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Similar questions

The reaction of sodium thiosulphate with $I_{2}$ produces:

I_{2}

I_{2} + 2 N a_{2} S_{2} O_{3} \to 2 N a I + N a_{2} S_{4} O_{6}

I_{2}

(N a_{2} S_{2} O_{3})

(N a_{2} S_{2} O_{3}) + I_{2} ⟶ N a I + \dots \dots

(N a_{2} S_{2} O_{3} \cdot 5 H_{2} O)

2 N a_{2} S_{2} O_{3} + I_{2} \to 2 N a I + N a_{2} S_{4} O_{6}

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