The reaction of the benzyl chloride with sodium cyanide followed by reduction with hydrogen in the presence of nickel gives:

β

-phenyl ethylamine

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N-isobutylaniline

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benzyl amine

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aniline

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Solution

The correct option is A $β$ -phenyl ethylamine
Form the above question we get,
$\begin{matrix} C_{6} H_{5} C H_{2} C l N a C l - --- \to - N a C l C_{6} H_{5} C H_{2} C N H_{2} / N i - --- \to C_{6} H_{5} C H_{2} C H_{2} N H_{2} B e n z y l c h l o r i d e β - p h e n y l e t h y l a m i n e \end{matrix}$
Hence, the option $(A)$ is correct.

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