The reaction of zinc with dilute and concentrated nitric acid, respectively, produces:

N O_{2}

and

N O

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N O

and

N O_{2}

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N O_{2}

and

N_{2} O

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N_{2} O

and

N O_{2}

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Solution

The correct option is D $N_{2} O$ and $N O_{2}$
$Z n + H N O_{3} (d i l .) \to Z n (N O_{3})_{2} (a q) + N_{2} O + H_{2} O$
$Z n + H N O_{3} (c o n c .) \to Z n (N O_{3})_{2} + N O_{2} + H_{2} O$

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