Question

The reaction products of $C_6{H}_{5}OC{H}_3+HI\stackrel{\Delta }{\to }$ is :

• A. $C_6{H}_{5}OH+C{H}_{3}I$
• B. $C_6{H}_{5}I+C{H}_{3}OH$
• C. $C_6{H}_{5}C{H}_3+HOI$
• D. $C_6{H}_6+C{H}_{3}OH$

Answer 1

The correct option is A $C_6{H}_{5}OH+C{H}_{3}I$

Ethers can be reactive under ​drastic reaction conditions (high temperature, high concentration) due to the cleavage of the $C-O$ bond in presence of HI.
$\text{Ether + HI}\to \text{Alkyl Iodide + Alcohol}.$ Halide attacks at less hindered site to produce alkyl halide.
$C_6{H}_{5}OC{H}_3\stackrel{HI}{\to }{C}_6{H}_{5}OH+C{H}_{3}I$