The reaction(s) involved in the removal of temporary hardness of water by heating is/are:

C a (H C O_{3})_{2 (a q)} \to C O_{2 (g)} + H_{2} O_{(l)} + C a C O_{3 (s)}

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M g (H C O_{3})_{2 (a q)} \to C O_{2 (g)} + H_{2} O_{(l)} + M g C O_{3 (s)}

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both

A

and

B

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none of the above

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Solution

The correct option is D both $A$ and $B$
The reactions involved during the removal of temporary hardness of water are
$C a (H C O_{3})_{2 (a q)} \to C O_{2 (g)} + H_{2} O_{(l)} + C a C O_{3 (s)}$
$M g (H C O_{3})_{2 (a q)} \to C O_{2 (g)} + H_{2} O_{(l)} + M g C O_{3 (s)}$
Temporary hardness of water is due to the presence of bicarbonates of magnesium and calcium. It can be removed by boiling the water when soluble bicarbonates are converted into soluble carbonates which can be removed by filtration. This is shown by above reactions.
Temporary hardness can also be removed by treatment with a calculated amount of lime.
$C a (H C O_{3})_{2} + C a (O H)_{2} \to 2 C a C O_{3} + 2 H_{2} O$

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Consider the following reaction.
$C a C O_{3} (s)$ + $H_{2} O (l)$ + $C O_{2} (g)$ $\to$ $C a (H C O_{3})_{2} (a q)$

$\begin{matrix} Element & Number of atoms present \end{matrix}$
$\begin{matrix} Reactant side & Product side Calcium & 1 & 1 Carbon & 2 & Y Oxygen & X & 6 Hydrogen & 2 & 2 \end{matrix}$
Recognise $X$ and $Y$ . The value of $X + Y$ is___.