The reaction that takes place when $C l_{2}$ gas is passed through conc. $N a O H$ solution is :

oxidation

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reduction

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displacement

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disproportionation

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Solution

The correct option is C disproportionation
$3 C l_{2} + 6 N a O H \to N a C l O_{3} + 5 N a C l + 3 H_{2} O$
This a disproportionation in which a substance is simultaneously oxidized and reduced, giving two different products. Here the chlorine is oxidized to $N a C l O_{3}$ and reduced to $N a C l$ .
Disproportionation reaction is a reaction in which a substance is simultaneously oxidized and reduced, giving two different products.
Hence, option D is correct.

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