The reaction that takes place when $C l_{2}$ gas is passed through conc. $N a O H$ solution is:

Displacement

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Disproportionation

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Oxidation

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Reduction

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Solution

The correct option is B Disproportionation
$6 N a O H + 3 C l_{2} \to 5 N a C l + N a C l O_{3} + 3 H_{2} O$

Disproportionation as the oxidation state of chlorine goes from 0 to $- 1$ in $N a C l$ and to $+ 5$ in $N a C l O_{3}$ .

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