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Question

The reaction which proceeds in the forward direction is

A
NH3+H2O+NaClNH4Cl+NaOH
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B
2Cul+I2+4K+2Cu2++4KI
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C
Fe2O3+6HCl2FeCl3+3H2O
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D
SnCl4+Hg2Cl2SnCl2+2HgCl2
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Solution

The correct option is C Fe2O3+6HCl2FeCl3+3H2O
Analysing the options

Option A:

Fe2O3+6HCl2FeCl3+3H2O
  • Fe2O3 is a basic oxide it will react with strong acid HCl readily since acid-base reactions are spontaneous. Hence, this reaction proceeds in forward reaction.
  • As complete hydrolysis of FeCl3 will give Fe(OH)3.xH2O , but HCl will not be formed as a product of hydrolysis. So, reaction will not proceed in backward direction.


Option B:

NH3+H2O+NaClNH4Cl+NaOH

Since NaOH is a strong base, it will react with NH4Cl (a salt of strong acid and weak base) to give NH4OH(NH3+H2O) and NaCl

Also, since the salt of strong acid and strong base (NaCl) does not undergo hydrolysis, so, reaction will proceed from strong to weak side i.e., in backward direction only.

Option C:

SnCl4+Hg2Cl2SnCl2+2HgCl2

  • In SnCl2, Sn exists in +2 oxidation state and in SnCl4, it exists in +4.
  • Since Sn2+ has reducing nature as Sn is more stable in +4 state, reaction can go in backward direction.
  • The Sn2+ ions convert readily to Sn4+ ions because the Sn(IV) oxidation state is more stable than Sn(II).
  • Thus, this reaction proceeds in backward direction.

Option D:

2Cul+I2+4K+2Cu2++4KI

Because of the reducing nature of I(iodide ion) of strong electrolyte KI (completely dissociated), Cu2+ gets reduced back to CuI. Thus, this reaction also goes in the backward direction also.


Hence, option (A) is correct.

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