Zn+CuSO4→Cu+ZnSO4
Mass of Zn=10g.
Volume of CuSO4=200mL
Total solid at end of reaction =9.810g
Cu deposited =?
[CuSO4]=?
Moles of Zn=1065.3=0.153
Let x mole (Zn) react with CuSO4
∴ Moles of unreacted Zn=0.153−x
(0.153−x)×65.3massofZn+63.54xmassofCu=9.81
x=0.1036
∴ moles of Cu=0.1036
(1) Mass of Cu=0.1036×63.54
=6.58g
(2) Molarity of CuSO4=x200×1000
=0.1036×1000200
=0.518M