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The reactions...

Question

The reactions $P C l_{5} (g) ⇌ P C l_{3} (g) + {C l}_{2} (g) a n d C O C l_{2} (g) ⇌ C O (g) + {C l}_{2} (g)$ are simultaneously in equilibrium at constant volume. A few moles of $C o (g)$ are introduced into the vessel. After some time, the new equilibrium concentration of:

A

P C l_{5}

will remain unchanged

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B

{C l}_{2}

will be greater

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C

P C l_{5}

will become less

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D

P C l_{5}

will become greater

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Solution

The correct option is C $P C l_{5}$ will become less
Solution
$P C l_{5} = P C l_{3} + C l_{2}$
$C O C l_{2} = C O + C l_{2}$
These reactions are in equilibrium at constant volume
When moles of CO are increased this shifts the reaction (2) Backwards and moles of $C l_{2}$ decreases.
Decrease of moles of $C l_{2}$ affect the equilibrium of reaction (1) and shifts the reaction forward.
This decreases moles of $P C l_{5}$
The correct answer is C

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