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Impedance Triangle

The reading o...

Question

The reading of A . C ammeter and voltage across capacitor in the given circuit are

2 amp,

20 V

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5

amp,

50 V

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3

amp,

30 V

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4

amp,

40 V

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Solution

The correct option is B $5$ amp, $50 V$
A.C ammeter reads the rms value of current
$i_{r m s} = \frac{i_{0}}{\sqrt{2}}$
and $i_{0} = \frac{V_{0}}{Z}$

$V_{0} = 100 V$

$Z = \sqrt{R^{2} + (X_{L} - X_{C})^{2}}$
$= \sqrt{10^{2} + 10^{2}} = 10 \sqrt{2} Ω$

$\Rightarrow i_{0} = \frac{V_{0}}{Z} = \frac{100}{10 \sqrt{2}} = \frac{10}{\sqrt{2}} A$

$∴ i_{r m s} = \frac{10}{2} = 5 A$

Voltage across capacitor $V_{C} = i_{r m s} \times X_{C}$
$= 5 \times 10 = 50 V$

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The reading of A . C ammeter and voltage across capacitor in the given circuit are

The correct option is B 5 amp, 50 VA.C ammeter reads the rms value of current irms=i0√2 and i0=V0Z V0=100 V Z=√R2+(XL−XC)2 =√102+102=10√2 Ω ⇒i0=V0Z=10010√2=10√2 A ∴irms=102=5 A Voltage across capacitor VC=irms×XC =5×10=50 V