Question

The reading of the ammeter in the figure is :
(internal resistance of battery is zero)

• A. 0 A
  
• B. 9/10 A
  
• C. 3.5 A
  
• D. 2A

Answer 1

Answer: (D)

2A

In a parallel circuit, the current through a resistance $R$ in parallel is given by $i_R=\frac{V}{R}$. So in this given circuit, the current through the ammeter will be $\frac{10}{5}=2A.$