The reagent(s) for the above conversion, is /are:

alcoholic KOH

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alcoholic KOH followed by

N a N H_{2}

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aqueous KOH followed by

N a N H_{2}

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Z n / C H_{3} O H

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Solution

The correct option is B alcoholic KOH followed by $N a N H_{2}$
Option $B$

$1, 2$ dibromo ethane under the presence of alcoholic potassium hydroxide followed by sodamide.
On treatment with Sodamide $N a N H_{2}$ , repeated de-hydrogenation and dehalogenation occurs which finally gives ethyne. Potassium hydroxide acts as calalyst.
Mechanism:

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