The correct option is A CuCl2
S2−+CuCl2→CuS↓(black ppt)SO2−4+CuCl2→CuSO4(soluble)
Thus, CuCl2 selectively precipitates S2−.
S2−+BaCl2→BaS(soluble)SO2−4+CuCl2→BaSO4↓(white ppt)
Thus, BaCl2 selectively precipitates SO2−4.
S2−+Pb2+→PbS↓(black ppt)SO2−4+Pb2+→PbSO4↓(white ppt)
S2− and SO2−4 both are precipitated.
S2−+Na2[Fe(CN)5NO]Sodium nitroprusside→Na2[Fe(CN)5NOS]Violet colourBut no colour with SO2−4.