The reagent that can effect the following conversion is:

(i) B r_{2} / C C l_{4}, (i i) N a N H_{2} (excess) / N H_{3} then C H_{3} - I, (i i i) N a / N H_{3}

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(i) B r_{2} / C C l_{4}, (i i) L i N H_{2} (excess) / N H_{3} then C H_{3} - I, (i i i) N a / N H_{3}, (i v) O s O_{4} then hydrolysis

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(i) B r_{2} / C C l_{4}, (i i) L i N H_{2} (excess) / N H_{3} then C H_{3} - I (e x c e s s), (i i i) H_{2} / Lindlar's catalyst, (i v) O s O_{4} then N a H S O_{3}

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(i) N a N H_{2} (4 eq) / N H_{3} then C H_{3} - I (e x c e s s), (i i) O s O_{4} then N a H S O_{4}

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Solution

The correct option is C $(i) B r_{2} / C C l_{4}, (i i) L i N H_{2} (excess) / N H_{3} then C H_{3} - I (e x c e s s), (i i i) H_{2} / Lindlar's catalyst, (i v) O s O_{4} then N a H S O_{3}$

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