The reagent that converts a 1- amide to a 1- amine without changing the number of C atom isA- Br 2- NaOHB- NaOBrC- LiAlH 4D- KMnO 4

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Standard XII

Chemistry

Chemical Properties of Ethers

The reagent t...

Question

The reagent that converts a $1^{\circ}$ amide to a $1^{\circ}$ amine without changing the number of C atom is

B r_{2} + N a O H

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N a O B r

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L i A l H_{4}

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K M n O_{4}

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Solution

The correct option is C $L i A l H_{4}$
$L i A l H_{4}$ is a strong reducing agent

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The Conversion of an amide by action of NaOH and $B r_{2}$ to primary amine that has one carbon less than the starting amide is known as Hofmann-Bromamide reaction.

$R - O | | C - N H_{2} B r_{2} + N a O H - ------ \to (o r) N a o B r R - N H_{2} + N a B r + N a_{2} C O_{3}$

The Conversion of an amide by action of NaOH and $B r_{2}$ to primary amine that has one carbon less than the starting amide is known as Hofmann-Bromamide reaction.

$R - O | | C - N H_{2} B r_{2} + N a O H - ------ \to (o r) N a o B r R - N H_{2} + N a B r + N a_{2} C O_{3}$

Q. Write and name the reaction to prepare amine containing less number of carbon atoms from acid-amide.

Q. (1) How will you convert an amide into an amine having one carbon less than the starting compound
(2) Name the reaction

Q. Assertion :In Hofmann bromide reaction, the amine formed has one carbon atom less than the parent

1^{o}

amide. Reason: N-methyl acetamide undergoes Hofimann bromamide reaction.

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The reagent that converts a 1∘ amide to a 1∘ amine without changing the number of C atom is

The correct option is C LiAlH4 LiAlH4 is a strong reducing agent

The reagent that converts a $1^{\circ}$ amide to a $1^{\circ}$ amine without changing the number of C atom is

The correct option is C $L i A l H_{4}$
$L i A l H_{4}$ is a strong reducing agent