The reagents, ammonium chloride and aqueous ammonia will precipitate :

B i^{3 +}

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P b^{2 +}

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M g^{2 +}

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F e^{3 +}

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Solution

The correct options are
A $B i^{3 +}$
C $P b^{2 +}$
D $F e^{3 +}$
(a) $B i^{3 +} + 3 N H_{4} O H ⟶ B i {(O H)}_{3} ↓ (w h i t e) + 3 N H_{4}^{+}$

(b) $P b^{2 +} + 2 N H_{4} O H ⟶ P b {(O H)}_{2} ↓ (w h i t e) + 2 N H_{4}^{+}$

(c) Due to common ion effect of $N H_{4}^{+}$ , the $O H^{-}$ ion concentration is not excess enough to precipitate $M g^{2 +}$ as $M g {(O H)}_{2}$ because of its high solubility product.

(d) $F e^{3 +} + 3 N H_{4} O H ⟶ F e {(O H)}_{3} ↓ (r e d d i s h - b r o w n) + 3 N H_{4}^{+}$ .

So, the correct options are $A$ , $B$ and $D$

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